H2S + KMNO4 + H2SO4 → S+ MNSO4 + KHSO4 + H2O BALANCE BY OXIDATION

     

Hydrogen sulphide, potassium permanganate, & sulfuric acid (H2S KMnO4 H2SO4) are available in almost all chemical labs across the World. In the H2SO4 medium, KMnO4 và H2S react mainly. The reaction is a Redox reaction.

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H2S KMnO4 H2SO4

The chemical compound with the chemical formula H2S is Hydrogen sulfide. It is a colorless gas with rotten eggs ‘ distinctive foul smell. Besides it is very poisonous as well as corrosive và flammable also.

Potassium permanganate is a compound and medication of inorganic chemical substances. It is a strong oxidizing agent. KMnO4 is a salt consisting of K+ and MnO4 -1 ion and has the chemical formula KMnO4. Lớn offer intensely pink or purple alternatives, it dissolves in water. In Solid-state it forms prismatic purplish-black glistening crystals.

Sulphuric acid is indeed a mineral acid having a molecular formula H2SO4 It is a colorless, odorless, and syrupy liquid that is soluble in water. In this reaction, it acts as an acidic medium only.

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Hydrogen sulphide reacts with potassium permanganate và sulfuric acid

Hydrogen sulphide reacts with potassium permanganate & sulfuric acid khổng lồ produce Sulfer, Manganese Sulfate, potassium sulfate as well as water.


KMnO4 + H2S + H2SO4 = S + + K2SO4 + MnSO4 + H2O

Now by using the ion-electron method we can balance the Oxidation-Reduction reaction.

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Ion-Electron method

Ion-electron method is a very effective method to balance equations of the Redox reactions. As the above reaction is a redox reaction, we can use the ion-electron method to balance the reaction equation. Let’s try-

The skeleton reaction for the redox reaction is-


KMnO4 + H2S + H2SO4 = S + + K2SO4 + MnSO4 + H2O

Here,The Oxidizing agent: KMnO4 or MnO4-1The Reducing agent: H2S or, S-2

Reduction Half Reaction:

⇒ MnO4 -1 +5e + 8H+  = Mn2- + 4H2O … …. …. …. (1)

Oxidation Half Reaction:


⇒ S-2 – 2e– = S … … … … (2)

Now,

equation (1)x2 + (2)x5,

2MnO4-1 +10e– + 16H+  = 2Mn2- + 8H2O

5S-2 – 10e– = 5S

⇒ 2MnO4 -1 + 5 S-2 + 16H+ = 2Mn2- + 8H2O +5S

⇒ adding necessary ions và radicals we get,

⇒ 2KMnO4 + 5H2S + 3H2SO4 = 5S + K2SO4 + 2MnSO4 + 8H2O

“Answer”

⇒2KMnO4 + 5H2S + 3H2SO4 = 5S +K2SO4 + 2MnSO4 + 8H2O

Click to readily understand ion-electron balancing redox reaction

KMnO4 + H2O2 + H2SO4 = O2 + MnSO4 + K2SO4 + H2O

FeSO4 + KMnO4 + H2SO4 = Fe2(SO4)3 + MnSO4 + H2O + K2SO4

NaCl + KMnO4 + H2SO4 = Cl2 + MnSO4 + Na2SO4 + K2SO4 + H2O

K2Cr2O7 + FeSO4 + H2SO4 = Cr2(SO4)3 + Fe2(SO4)3 + K2SO4 + H2O


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