Solve Inequalities With Step

     
All equations of the size ax^2+bx+c=0 can be solved using the quadratic formula: frac-b±sqrtb^2-4ac2a. The quadratic formula gives two solutions, one when ± is addition & one when it is subtraction.

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This equation is in standard form: ax^2+bx+c=0. Substitute 1 for a, -1 for b, và -1 for c in the quadratic formula, frac-b±sqrtb^2-4ac2a.
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x2-x-1=0 Two solutions were found : x =(1-√5)/2=-0.618 x =(1+√5)/2= 1.618 Step by step solution : Step 1 :Trying lớn factor by splitting the middle term 1.1 Factoring x2-x-1 The ...
(2x2)-x-1=0 Two solutions were found : x = -1/2 = -0.500 x = 1 Step by step solution : Step 1 :Equation at the over of step 1 : (2x2 - x) - 1 = 0 Step 2 :Trying khổng lồ factor by splitting the ...
3x2-x-1=0 Two solutions were found : x =(1-√13)/6=-0.434 x =(1+√13)/6= 0.768 Step by step solution : Step 1 :Equation at the end of step 1 : (3x2 - x) - 1 = 0 Step 2 :Trying to lớn factor ...
8x2-x-1=0 Two solutions were found : x =(1-√33)/16=-0.297 x =(1+√33)/16= 0.422 Step by step solution : Step 1 :Equation at the over of step 1 : (23x2 - x) - 1 = 0 Step 2 :Trying lớn ...
10x2-x-1=0 Two solutions were found : x =(1-√41)/20=-0.270 x =(1+√41)/20= 0.370 Step by step solution : Step 1 :Equation at the kết thúc of step 1 : ((2•5x2) - x) - 1 = 0 Step 2 :Trying to lớn ...

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How vì you find the value of the discriminant and determine the nature of the roots displaystyle-2x^2-x-1=0 ?
https://socratic.org/questions/how-do-you-find-the-value-of-the-discriminant-and-determine-the-nature-of-the-ro-1
-7, no real rootsExplanation:The discriminant is found using the equationdisplaystyleb^2-4ac . Substitute the values from your equation into this one so:a = -2 b = -1 c = -1the ...
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All equations of the size ax^2+bx+c=0 can be solved using the quadratic formula: frac-b±sqrtb^2-4ac2a. The quadratic formula gives two solutions, one when ± is addition và one when it is subtraction.
This equation is in standard form: ax^2+bx+c=0. Substitute 1 for a, -1 for b, and -1 for c in the quadratic formula, frac-b±sqrtb^2-4ac2a.
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the khung x^2+bx=c.
Divide -1, the coefficient of the x term, by 2 to get -frac12. Then add the square of -frac12 khổng lồ both sides of the equation. This step makes the left hand side of the equation a perfect square.
Factor x^2-x+frac14. In general, when x^2+bx+c is a perfect square, it can always be factored as left(x+fracb2 ight)^2.

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Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. Khổng lồ use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
Let r và s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B và the sản phẩm of factors rs = C
Two numbers r và s sum up to lớn 1 exactly when the average of the two numbers is frac12*1 = frac12. You can also see that the midpoint of r & s corresponds to lớn the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r & s are equidistant from the center by an unknown quantity u. Express r và s with respect khổng lồ variable u.
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